I have replaced all the ccfl tubes, still didn't fix the issue.
I have done some measurements on the balancers with the common harness removed and the on the left side test points were much lower then the right ones. Around 4-5.5V on the left and the right were high as before.
Not sure if this means anything though.
It's very confusing this TV, since it has two balancers and two inverters, it's a first for me a TV like this.
In the manual it says that, that side where the tubes are darker, there the problem is.
But if I read about how many times wants to start up, like three times if it's an inverter problem is detected, I don't see that happening. I don't even see two time startup either, which suggests a balancer error.
To me, it seems like it's starting up once and then shows the error code.
The darker side is the D4 inverter side.
If it would be an inverter problem, the tubes wouldn't even turn on, am I right?
They turn on for two seconds, so the inverter is fine. Though in the manual it suggests an inverter problem in this case.
I'm very confused, I would appreciate some help. There are four balancer boards and two inverters. It would be to expensive, to start replacing them all, one by one.
17.46V on the 100 Ohms resistor? I cannot see how it can develop that much voltage on the resistor. I need to look at the balancer board to see how it is all connected. You do have high voltage for sure, otherwise you will not be getting output voltage on the Cathode side.
There are 4 pins on the primary side of the transformers. The two inner ones send the signal to the diode. One end it seems like it's going to the ground, at least by measuring with the Ohm meter shows 0.3 to the ground. The other end goes to the diode.
The outer pins are going to the other transformer's outer pins. They are connected in series between them. If I measure on one board from one end to the other end, with the joining harness between other balancer boards, each balancer board shows 6.0 Ohm. All inner coil shows 0.5-0.7 Ohm. All secondary coils are 268-272 Ohms.
It seems like all the transformers are fine. All the ccfl tubes I have replaced from another TV, which didn't have ccfl tube issues(had tab bonding issues).
The only thing left, is the comparator on the balancer board and the two inverters.
The weakest side is the D4 inverter (next to the PS).
How can I be sure that an inverter is working or not? The way I have tested it, is by setting the multimeter to VAC and holding the red probe close to the pink wire at the output of the inverter.
The D4 inverter showed less then at the D5 inverter.
But at the balancer that high voltage, can be caused by a bad inverter?
Does the LD stay at 11~12VDC with the resistors in place?
"There are 4 pins on the primary side of the transformers" they are actually secondary side per page 45~46. they are connected in series and not connected to ground.
I will measure it today.
In that drawing it seems like there are only two coils, but to me it seems like there are two on one side and one on the other(tubes).
I will look at this again and try to figure out where the pins are actually going.
At LD, still drops the voltage to 0.7V with a 120 Ohm resistor on the right balancer boar and one one on the left balancer board.
There is only 10.65V, not 12V.
"At LD, still drops the voltage to 0.7V with a 120 Ohm resistor on the right balancer boar and one one on the left balancer board."
Are you saying the LD is at 0.7V or 10.65V (per training manual, it should be around 11~12V, 10.65 is close enough)
So it did trip the comparator which is strange since we grounded the input to the comparator IC using the resistor. You may be able to disconnect that LD line and feed it with external 12V power source to fool he main board that the balancer circuit is OK. I did not have a chance to probe my balancer boards yet to see if any one of the secondary side of the transformer is tied to the circuit ground as it is measured on you board.
Just to be sure, I'm not doing something stupid. These diodes are double diodes, right? The one pin toward the comparator is the cathode and the two pins going toward the test points are the anodes.
Yes, the center pin is the common Cathode, the other are the Anode for the each diode. They are setup as a simple rectifier to produce positive voltage to trip the comparator IC.
OK, I look at my board, the two inner pins of the transformer, on of the inner pin is connected to ground, the other pin is connected to the Anode of the dual diode.
the outer two pins are connected in the loop with the other transformer. So basic diagram does not show exact setup, that is why it is confusing. The two outer pins has no connection to ground.
So we ground the Cathode but the comparator still tripped some how.
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