For some reason I'm just not going to let this 19" TV defeat me. I guess because I have a schematic to work from I feel like I'm oh so close.
History- while adding a turn-on circuit I let a small screw roll under the power board. Worked through all of that circuitry, probably replacing a MOSFET and PWM controller that were not bad but I was following the service manual. Finally figured out that the power supply is in working order when the inverter section (for the backlights) is disconnected. When the +12 supply to the inverter is disconnected the +12 and +5 will come up properly. The measured resistance value across the +12 and ground of the inverter circuit is approximately 5 ohms which can't be correct.
See attached, I traced out the circuit and the only logical place for the resistance to drop to that level is across one or both of the inverter MOSFET's, Q805 and Q806 if one or both are shorted internally. C811 and C812 are both good and have been removed. With these out the resistance is still about 5 ohms. +12 is highlighted in yellow and ground is in red. As you can see the only place they could meet up with such low resistance is Q805 and Q806, unless C801 or C802 and IC801 somehow became shorted.
Thoughts on replacing the MOSFET's? Anything else I could test to confirm that they are bad? If only one is bad and I pulled it out of the circuit should the +12 rail come back up and light up the other MOSFET, thereby lighting up half of the screen?
Val
History- while adding a turn-on circuit I let a small screw roll under the power board. Worked through all of that circuitry, probably replacing a MOSFET and PWM controller that were not bad but I was following the service manual. Finally figured out that the power supply is in working order when the inverter section (for the backlights) is disconnected. When the +12 supply to the inverter is disconnected the +12 and +5 will come up properly. The measured resistance value across the +12 and ground of the inverter circuit is approximately 5 ohms which can't be correct.
See attached, I traced out the circuit and the only logical place for the resistance to drop to that level is across one or both of the inverter MOSFET's, Q805 and Q806 if one or both are shorted internally. C811 and C812 are both good and have been removed. With these out the resistance is still about 5 ohms. +12 is highlighted in yellow and ground is in red. As you can see the only place they could meet up with such low resistance is Q805 and Q806, unless C801 or C802 and IC801 somehow became shorted.
Thoughts on replacing the MOSFET's? Anything else I could test to confirm that they are bad? If only one is bad and I pulled it out of the circuit should the +12 rail come back up and light up the other MOSFET, thereby lighting up half of the screen?
Val
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