Re: LED Driver board Question
Fun fact: When I put it back in the guy asked could we increase the backlight brightness. I thought it looked fine but with the replacement I've made it has reduced the brightness, so the resistance value we were talking about does seem to have something to do with the level of current passing through the LEDs.
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Re: LED Driver board Question
Okay, I've put it all back together. A million screws of course.
Just to re-iterate, I have not made any changes since the start of the thread. I have replaced the open 2R and R330 resistors with one 2R2 resistor and it has been on for four days solid without any issues.
I'm gonna run with this. thanks.
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Re: LED Driver board Question
If I swop the 2R2 for a 1 ohm resistor and measure the current will that settle the argument
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Re: LED Driver board Question
Originally posted by Diah View Postdon't find excuse for wrong statement.. this Edge LED back light double cell, this why i asked him if there was wrong,,but OP clarified its Edge.
now about Edge.. did you asked your self why here no much threat about this type ?
allot of answer here.. start from the Freq. to currents.. to circuit .. OP upload photos easy to 2R2 & R332 are NOT sensing current but to just protect the PWB LED section.
1) Do you understand what constant current circuit does and how it maintain constant current through the LED's?
2) As you can see, pin 3 of the IC U1 is monitoring the Vdrops on the resistor, if the Vdrops staring to change, it means the current through the LED is changing, so pin 3 of the IC is sensing that Vdrops to maintain the current at set level by changing the PWM that drive the power MOSFET Q7,.
when current is constant, the Vrops will be constant.
To maintain something at constant, you need feed loop, any person that knows electronics will understand that.
3) Did you look up the spec sheet of U1 to find out what that IC is for? I bet you did not and that is why you do not understand the circuit. I ask OP for the P/N and did the research so I can see how this board works.
4) So you are saying if you put LED light source on the edge, instead of backlit, the LED driver circuit for maintaining current is not the same topology? Who teach you that?
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Re: LED Driver board Question
Originally posted by budm View PostThey probably have it set to about 90% PWM which is typical for Signage Display, which is still high and that is why the resistor burn out.
now about Edge.. did you asked your self why here no much threat about this type ?
allot of answer here.. start from the Freq. to currents.. to circuit .. OP upload photos easy to 2R2 & R332 are NOT sensing current but to just protect the PWB LED section.
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Re: LED Driver board Question
Originally posted by JonathanAnon View PostI put the clamp on the two positive wires coming out of the driver board feeding the LED strips. Does seem low to me but that is what it reads.
Sorry Bud, I meant to say this - there is no means for the user to change the backlight through brightness setting or the like. There is no remote control. So the backlight current will be fixed.
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Re: LED Driver board Question
LOL.. some user may don't Know or missed to read this threat carefully.. this is STORE DISPLAY
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Re: LED Driver board Question
Originally posted by budm View PostWhere did you put the Clamp on meter?
Post #28 Vdrops 200mV/2R2 = 0.090A = 90mA.
Are the reading done at full backlights set to max?
Sorry Bud, I meant to say this - there is no means for the user to change the backlight through brightness setting or the like. There is no remote control. So the backlight current will be fixed.
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Re: LED Driver board Question
Originally posted by JonathanAnon View PostHey guys,
It's been on for two days solid with the 2R2 resistor. Backlight is more than adequate.
Voltage drop on the 2R2 resistor is 200mV
you have edge LED double cell ,, not much will happen as the set store display., back light are working on one level and the 2R will be protect to PWB.
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Re: LED Driver board Question
Originally posted by JonathanAnon View PostOkay I used my induction ammeter to measure the current as well. There's no obvious location to break the circuit to introduce a series ammeter, so clamp is the best I'm gonna have for the moment.
200mV voltage drop across 2R2 resistor. 200mA current on the induction clamp.
P=VxI = 0.2V x 0.2A = 0.04 Watts.
So, the 2R2 resistor will have to dissipate 40mW.
Post #28 Vdrops 200mV/2R2 = 0.090A = 90mA.
Are the reading done at full backlights set to max?
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Re: LED Driver board Question
Okay I used my induction ammeter to measure the current as well. There's no obvious location to break the circuit to introduce a series ammeter, so clamp is the best I'm gonna have for the moment.
200mV voltage drop across 2R2 resistor. 200mA current on the induction clamp.
P=VxI = 0.2V x 0.2A = 0.04 Watts.
So, the 2R2 resistor will have to dissipate 40mW.
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Re: LED Driver board Question
Hey guys,
It's been on for two days solid with the 2R2 resistor. Backlight is more than adequate.
Voltage drop on the 2R2 resistor is 200mV
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Re: LED Driver board Question
I have an LED tester in the post Bud, can't get there here in any shop in Ireland somehow. But it should be here shortly. There's a big digitiser fitted in to the main steel frame - So it's interactive as well. It's actually really cool when it's back together. Would be a hell of a gaming machine if I downloaded the MAME emulator.
Do you mean that each string has 26 LEDs and 4 of these strings are then connected in parallel?Last edited by JonathanAnon; 08-12-2020, 01:36 PM.
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Re: LED Driver board Question
"The LEDs in my version of the screen are all at the bottom of the screen, there are two LED strips and each has four parallel sets of 26 LEDs. The back of the panel says 720ma / 78-89V"
Do you mean that each string has 26 LEDs and 4 of these strings are then connected in parallel?
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