I've an old Canadian Tire 37-9452 Halogen Spotlight, which seems to have 2mln candle H3 6v 25W halogen lamp, powered by lead battery SD620 6v 2Ah (cycle 7.25-7.45, standby 6.8-6.9 Yuyao SanDing Electric Ltd, size 3x1.85x1.5 inch), which is charged by the power adapter TL-9B 9V 300mA.
The battery is now dead, and I can't find replacement of the same size that would fit inside the Spotlight. Can you guys suggest & link a suitable battery model? May be using Li-Ion battery will be the best choice, but which one and how to charge it regularly without the Spotlight disassembly, as the internal charger is very basic and likely won't do it?
Alternatively, I'd use it without a battery, by powering directly from a 6V 2A power adapter, connected to the same female connector on the Spotlight. The question is, how to modify the PCB schematics to preserve all switches functionality (side/main lamp switch, handle lamp On/Off, red power led), but power the lamp directly? Current PCB layout only seems to charge the battery, which in turn powers the lamp if there is any remaining charge in the battery.
Interesting is, the battery is 6v 2A, but the power adapter used is 9V 300mA, and in fact its idle voltage is 18V DC as measured by a multimeter. Why is that?
The battery is now dead, and I can't find replacement of the same size that would fit inside the Spotlight. Can you guys suggest & link a suitable battery model? May be using Li-Ion battery will be the best choice, but which one and how to charge it regularly without the Spotlight disassembly, as the internal charger is very basic and likely won't do it?
Alternatively, I'd use it without a battery, by powering directly from a 6V 2A power adapter, connected to the same female connector on the Spotlight. The question is, how to modify the PCB schematics to preserve all switches functionality (side/main lamp switch, handle lamp On/Off, red power led), but power the lamp directly? Current PCB layout only seems to charge the battery, which in turn powers the lamp if there is any remaining charge in the battery.
Interesting is, the battery is 6v 2A, but the power adapter used is 9V 300mA, and in fact its idle voltage is 18V DC as measured by a multimeter. Why is that?
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