Re: Wavetek Model 130 Function Generator - Power supply problem
This fix is a good example of the importance of visual inspection. I say that to someone who is a trained inspector, I guess. Good fix.
Wavetek Model 130 Function Generator - Power supply problem
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Re: Wavetek Model 130 Function Generator - Power supply problem
BTW, it would have saved lots of times if follow my suggestion on post #2.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Thanks for the follow-up. When something defy the logic, it is when you have to recheck the works.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Put everything back together and hooked up the output to the scope - ALL IS WELL. All ranges of frequencies look good on my scope as well as the Fluke meter.
So to recap: The replacement of Q17 and 18 would have done the trick if some goofball (ME) would have installed it right the first time. And I used to work as a board inspector/tester. I used to get on the assemblers for making mistakes like that. The shoe is on the other foot today.
Bud, Longbow, Redwire - thanks for all the assistance.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
zero volts on base of Q18.
-6.6 volts on anode of CR19
That R88 measures good out of circuit and point to point ohms out to its connections. 29 volts on one side. zero on the other. its not smoked either. I dont think its dropping the voltage.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
I actually got an Idea. I'm just wondering if this would work. What if I simply bypass all this crap by eliminating this section of the power supply by implementing two 15 volt regulator IC's?
Here is my plan:
Pull Q17,18,and 19.
pull CR19
Input of 15V regulator at +29V, ground TP1, output to "J"point past TP2 leaving jumper open. I just have to heatsink it to something.
Do you guys think this could work or am I going too far? I just think this circuit is over complicated for DC power supply of 15V.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
You are getting negative Voltage through R108, 106.
As I indicated, R8 is the Bias resistor, so when IC6 is removed then you should have over 20V on the Emitter of Q17.
So what DCV do you have at each end of R8?
Is one end of R8 actually making electrical connection to the Base of Q18?
What DCV do you have at the Base of Q17?
What DCV do you have at the Base of Q18?
Right now Q17/18 is not getting the bias current through R8.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Well, I removed both jumpers. I had to test a theory of that a friend had suggested that something downstream may have been loading down the circuit somehow.
With jumpers removed
TP3 shows -19VDC
TP2 shows -3.6VDC
The only clue that I gain now is not only that the problem is definitely in this area for sure but... why negative 3.6 at TP2?Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
I did check that R88, all is well there (resistively).
Ok, do we agree that if I lifted the jumper at TP2 and TP3, thus, in my mind, disconnecting the load from the power supply, I should have the rail voltages for sure. Please correct me if I'm wrong.
Just to refresh - what has been changed so far:
Q17
Q18
Q19
IC6
29VDC at Q17 and Q18 Collector (same point)
0.8VDC at Q17 emitterLeave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
ok. I replaced Q18 and Q19 Still no voltage on the positive 15V rail.
I pulled Q17. It tested good out of circuit but I replaced it anyways cause I had the new one and its kinda hard to get back in. Same problem.
So.... I pulled IC6 to see if it was pulling down the voltage somehow. Still no voltage for VCC with it removed.
Next I disconnected the jumper at TP2 separating R102 and R103. Still no voltage at TP2Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
ok. I replaced Q18 and Q19 Still no voltage on the positive 15V rail.
I pulled Q17. It tested good out of circuit but I replaced it anyways cause I had the new one and its kinda hard to get back in. Same problem.
So.... I pulled IC6 to see if it was pulling down the voltage somehow. Still no voltage for VCC with it removed.
Next I disconnected the jumper at TP2 separating R102 and R103. Still no voltage at TP2Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
I had to take a business trip to DC yesterday. Im back home and my parts are here now. Q18 showed no voltage when trying the diode test out of circuit. Q17 tests ok. I'm going to replace the two that I have out (Q18,19).Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Q19 is bad if that is what you are seeing between C and E which I mention for you to test in post #2.
"Q18 out of circuit
CE both directions - open
EB both directions - open
BC both directions - open'
So how does it test when using Diode mode for Q18?
How about Q17?Last edited by budm; 04-19-2017, 01:27 PM.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
.8v on solder side of IC7 pin 7 too, which is weird if this side is working.
They are both can type of IC's so I can only get to the bottom/solder side of each - but directly on the pins themselves. Solder joints checked as well.
Q19 Out of circuit
620 ohms from C to E. Is this ok? Shouldnt it be open?
e to b 2 meg one direction and 330 K the other.
b to c 2 meg one direction and 343 K the other.
Q18 out of circuit
CE both directions - open
EB both directions - open
BC both directions - open
Are both bad or just Q18?Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
DG, the comparison technique is ok but in the end it won't tell you why the voltages are different. It's easy to get lost in that. You have to roll back to circuit theory. Or test the parts in the section that is not working.
Q17/Q18 make a Darlington pass transistor with R88 supplying base drive to turn them on. IC6 turns them off when the output goes over +15V.
cathode CR19 = 6.4V so Q18 or Q17 E-B is OPEN
IC6 is powered from the output of this vreg, so it will not be doing anything until the pass transistors start working and give IC6 sufficient voltage to run.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
How about q17, q18?
How about +vcc on pin 7 of IC6, IC7, what do you have RIGHT AT THE IC PIN7 of BOTH ICs?Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Q19 is not shorted. I checked. How about uA096? Is there a way to check this for correct operation? I ohmed out point to point of the components in question.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
I will check for Q19 and report back.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
DG, we are going about this the wrong way. Instead of stabbing the circuit in random places, take a moment to predict what you SHOULD be seeing in the circuit rather than making sense of a bunch of unrelated voltage measurements.
First, you know the output should be +15v (obviously it isn't at the moment)
Then, you must have 15.6 volts at Q17 base and 16.2 volts at Q18 base.
Q19 is there to protect Q17 in the event of over-current. If it is shorted, it would then shut down the 15 volts. Thus, check for shorted Q19 first.
CR19 zener is probably about 15 volts (check in the parts list). That should put the d.c. level of IC6 pin 6 at around 0 volts.
Other than that, CR21 zener is the reference for the whole supply, along with R104 adjustment. As you say, if you have -15 volts, then the reference zener is working along with the adjustment R104. That means you DO have +15 volts up until some point around TP2 or J you have a cracked circuit trace. There is no way that you could have -15 volts without the +15 because IC7 pin 2 depends upon the +15 volts being correct. At this point your tools are a magnifying glass and an ohmmeter.Leave a comment:
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Re: Wavetek Model 130 Function Generator - Power supply problem
Here are some other voltages to work with as I do some comparative probing around. All of these voltages will be from TP1 to each location.
Cathode of CR 11 = 29VDC
Anode of CR 14 = -27 VDC
Cathode of CR19 = 6.4V Anode of CR19 = .05V
Anode of CR 20 = -17.9V Cathode of CR20 = - 11.3V
R93 side of base to Q22 = -15V
R92 side of base to Q19 = .79v
Where R91 and R90 come together = .8V
Where R94 and R95 come together = -16.6V
IC6 pin 6 = -3V
IC7 pin 6 = -1.8VLeave a comment:
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