It seems that what you mean is not what we understand... Would you please rephrase your inquiry about cap discharge. You will get the right answer/explanation...
Charge up the cap and see for yourself if it will hold the same voltage, that Rp is in parallel with the cap since no cap has perfect insulation between the two plates, it has very high resistance which will eventually drain the cap.
The Rp represent the real world cap circuit, not the circuit resistor.
If you design high Z circuit, you will know how important of the Rp will be. The leakage current can be in uA or mA range, no cap has perfect insulation between the two plates. http://www.newton.dep.anl.gov/askasc...0/phy00900.htm
It will still have self dis-charge due to it leakage resistance, Rp. Very important in high Z circuits.
Read the link on post 6.
No. This leakage (Rp) is through a resistor in parallel with a cap. A cap, especially a large electrolytic one, will hold a charge if cap is removed from a circuit. The charge will dissipate eventually over time, but too slowly enough that it will still hold a charge.
Capacitors always self-discharge (except when at a low voltage - they can have a battery effect!). Even when there is power being applied across the capacitor, it is discharging, but the power source keeps refilling the stored power reservoir (the capacitor/capacitance). This discharge is called leakage current.
The datasheets for the capacitors will specify the leakage current. A capacitor discharging fast, with no external power source applied, means either the leakage current is high, and/or the capacitance has dropped. Don't mistake this when evaluating a small value capacitor!
Not sure if he is asking about self-discharge, the charged cap will self-discharge (when it is disconnected from the source) the due to internal leakage resistance.
No, because of the phrase you mentioned: "when it was connected across the DC voltage." In that configuration, there is no discharge because DC is continuously applied to it. If the phrase is modified this way: "when it was connected across a bleed resister to ground," you'd be right. But, without connecting the cap's leads to themselves or to a circuit, there is little or no discharge.
I have understood that an electrolytic capacitor has a self healing effect when disconnected in such a way that, when it is disconnected after being charged in DC, its self-discharge resistance is much bigger that the resistance when was connected across the DC voltage.
Am I right? How much bigger?
I would like to know in depth this phenomena, could you bring me some hints about it ?
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