I just got trolled by one of these with no power. Getting 0V on ACDET for the BQ24780S charger IC, hence first MOSFET not being opened etc. The voltage divider resistors were both ok, 19V on the top of the first one, and the BQ IC was also blameless. Why 0V for ACDET?!
So thankfully the schematic provided here revealed all. The DC jack has a 2nd connection called ADP_ID (which I think provides that tiny click when you fully insert the adaptor). There is a FET PQ7 which is normally biased on by PR60/67 and will thus ground ACDET to 0V. This FET will only switch off when ADP_ID is grounded in the plug (presumably from the barrel of the adaptor plug), and you get your normal 2.6V.
I just got trolled by one of these with no power. Getting 0V on ACDET for the BQ24780S charger IC, hence first MOSFET not being opened etc. The voltage divider resistors were both ok, 19V on the top of the first one, and the BQ IC was also blameless. Why 0V for ACDET?!
So thankfully the schematic provided here revealed all. The DC jack has a 2nd connection called ADP_ID (which I think provides that tiny click when you fully insert the adaptor). There is a FET PQ7 which is normally biased on by PR60/67 and will thus ground ACDET to 0V. This FET will only switch off when ADP_ID is grounded in the plug (presumably from the barrel of the adaptor plug), and you get your normal 2.6V.
Replacing the DC jack fixed it. Go Acer
Yeah, this worthless design really sucks, had it plenty of times already on multiple Acer models with the small needlepin connector.
These are the only cases, where I never replace the jack - but bridge both sides to ground because I see absolutely zero point in this design.
I have one of these boards and have two caps shorting (See picture) anybody know what value they are, as the provided boardview does not seem to have them mentioned?
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