HP EliteBook 850 G5 without signs of life

[Sephir0th]

That's the BATGONE# indicator. If left side of the resistor connects to GND then you're good to go with a 0 Ohms resistor. If it isn't GND then you're typically good with 100KOhms.

[elgollo51]

That's the BATGONE# indicator. If left side of the resistor connects to GND then you're good to go with a 0 Ohms resistor. If it isn't GND then you're typically good with 100KOhms.

It uses an ISL9538H and the resistor is connected to pin 19 ACIN and does not go to GND on either end. I have already sent you a capture.

[Sephir0th]

Interesting, it looked like it would connect to Pin 25. However if this is ACIN then you are dealing with a voitage divider here. The resistor to GND on this track has to match too, to get ~3.6V at ACIN pin.

tl;dr simply calculate it.

[elgollo51]

Interesting, it looked like it would connect to Pin 25. However if this is ACIN then you are dealing with a voitage divider here. The resistor to GND on this track has to match too, to get ~3.6V at ACIN pin.

tl;dr simply calculate it.

The problem with the laptop was that there was a short and it damaged the ACIN line of pin 19 of this ISL9538H circuit, burning the resistor R60010 and I think it adulterated the resistor R60006 because it has an ohmic measurement of 2 Mohms, the resistor R60006 communicates end 2 to ACIN and end 1 to ADP_DEP of pin 24 of the ISL9538H, but neither of the 2 resistors R60010 and R60006 have an end to GND