I have one of those "2 seconds to black" problem, and is because 2 of the 4 CCFL are broken.
The top 2 CCFL still works, and I was wondering, how can I fool the inverter IC that there are 4 lamps?
The model of my power supply used by my monitor (Samsung 940N) is IP-35155A with the schematics attached.
What voltage do I have to apply on pin3 - OLP (Open Lamp Protection) on the SEM2005 IC, to prevent the stopping?
Also, why is there needed a protection for the inverter in case it doesn't have a load?
On the inverter output it says, "650V~/7.5mA". Can't I use only 3mA?
The top 2 CCFL still works, and I was wondering, how can I fool the inverter IC that there are 4 lamps?
The model of my power supply used by my monitor (Samsung 940N) is IP-35155A with the schematics attached.
What voltage do I have to apply on pin3 - OLP (Open Lamp Protection) on the SEM2005 IC, to prevent the stopping?
Also, why is there needed a protection for the inverter in case it doesn't have a load?
On the inverter output it says, "650V~/7.5mA". Can't I use only 3mA?
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