Re: Help diagnosing Pyle Receiver PTA66BT with burned resistors
You messed up badly about which power supply is for V+ (+ Voltage supplied by BURNT resistor) and the V- (Minus Voltage supplied by good resistor).
1) Your measurement: I continued testing the components along the V- path, the first resistor was .57 Ohms, the second resistor was .59 Ohms, and all three transistors measured .5 Ohms from E to C.
The section with 3 Transistors is for the V+ which is fed by the burnt out resistor. So why are you referring it as V-?
Since your resistance reading of the 3 Transistors (connected in parallel) E-C is 0.5 Ohms, these Transistors for the V+ ARE SHORTED!
2) Also these readings from you:
Burned Resistor to V+
Near leg: 5.4 Ohm
Far leg: 180 Ohms
(Yes these were both Ohms not Mega Ohms. I checked 5 times)
The resistance of the near leg of the resistor to V+ should be 0.5 Ohms because you indicated that the 3 Transistors E-C show 0.5 Ohms as you stated., you must recheck that, also see the schematic as how E and C of the Transistors are connected to the burnt resistor and to the V+ terminal.
3) I do not know why you are messing with the V- section. Hope fully you did not mess up putting the parts back in wrong.
4) Did you not look at so many pictures I spent so much time to provide to you? It clearly shows which one is for V+ (the one with burnt out 180 Ohms resistor) and V-.
5) My patience is running out due to getting bad data and attention not being made by OP after I spend so much time explaining and providing the pictures and the schematics. Nothing to do with being a noob, but for not paying attention and not think logically when looking own data.
6) We are up to over 40 posts and still getting wrong DATA.
Conclusion, you have shorted Transistors (3 are connected in parallel) in the V+ regulator circuit:
1) It can possible mean that the Loads on the V+ are shorted, more testing to be done.
2) If the Transistors shorted out first then more than 12V will be dumped to the loads connected to the V+ which can cause damage to the loads.
3) More damages could have been done to the loads when OP put in the new resistor but the Transistors were already shorted out so more than 12V is dumped into the loads again.
Originally posted by SluggerB
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1) Your measurement: I continued testing the components along the V- path, the first resistor was .57 Ohms, the second resistor was .59 Ohms, and all three transistors measured .5 Ohms from E to C.
The section with 3 Transistors is for the V+ which is fed by the burnt out resistor. So why are you referring it as V-?
Since your resistance reading of the 3 Transistors (connected in parallel) E-C is 0.5 Ohms, these Transistors for the V+ ARE SHORTED!
2) Also these readings from you:
Burned Resistor to V+
Near leg: 5.4 Ohm
Far leg: 180 Ohms
(Yes these were both Ohms not Mega Ohms. I checked 5 times)
The resistance of the near leg of the resistor to V+ should be 0.5 Ohms because you indicated that the 3 Transistors E-C show 0.5 Ohms as you stated., you must recheck that, also see the schematic as how E and C of the Transistors are connected to the burnt resistor and to the V+ terminal.
3) I do not know why you are messing with the V- section. Hope fully you did not mess up putting the parts back in wrong.
4) Did you not look at so many pictures I spent so much time to provide to you? It clearly shows which one is for V+ (the one with burnt out 180 Ohms resistor) and V-.
5) My patience is running out due to getting bad data and attention not being made by OP after I spend so much time explaining and providing the pictures and the schematics. Nothing to do with being a noob, but for not paying attention and not think logically when looking own data.
6) We are up to over 40 posts and still getting wrong DATA.
Conclusion, you have shorted Transistors (3 are connected in parallel) in the V+ regulator circuit:
1) It can possible mean that the Loads on the V+ are shorted, more testing to be done.
2) If the Transistors shorted out first then more than 12V will be dumped to the loads connected to the V+ which can cause damage to the loads.
3) More damages could have been done to the loads when OP put in the new resistor but the Transistors were already shorted out so more than 12V is dumped into the loads again.
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