I can't help myself boys Looking around the internet, youtube to be exact, I came across an interesting little gizmo that could not only prove very useful to me in the long run as an electronics enthusiast, but could also serve as a good learning exercise: a constant current load. I thought "well what a cool project...I could use something that can give the power supplies I occasionally mess around with a good workout".
The vid that inspired me is here. What the chap achieved is VERY tempting to replicate (100A load), but ultimately way overkill for my purposes, especially since I haven't actually designed one of these before and need to start small, so I'd say.....10A ? That's probably too much still (1A would probably do it for a beginner, but hey....think big ) The device is rather simple, or so it seems at first, because when I really began looking into it, I was quickly faced with one or two quirks I'd like to discuss.
I DID do my research do a degree, so let's go over this. The basic schematic is below. The main ingredients are a series-pass FET and sense resistor. I like to think of the FET as essentially shorting the PSU under test to ground through the resistor. For this reason, the resistor has to have a very small value so it doesn't burn up. The shunts the chap used in his project are 0.0015 ohm 50A shunts (yes, I much prefer using the whole value than using "MILLI..." etc....bare with us ). How do I know the value? For once, I happen to have the same exact shunts on hand (came with some of those panel ammeters you see on ebay...anyway) and also the current and voltage are stamped on the side, so here's where good ol' Ohm's law comes in to work out the voltage: V/R=I so 0.075V/0.0015 Ohms=50A...plain and simple (triple checked my math to make sure I don't make a fool out of myself for not knowing Ohm's law...which will probably happen anyway )
So now that we have the shunts, what do we do with them ? Our chap uses two in parallel to drop the resistance even more, but since I don't need to go too crazy with the current for now, 0.0015 ohms should be enough to achieve a 10a load. I have 3 of those shunts available, so my idea is to build 3 individual loads so I can stress multi-rail supplies simultaneously. My math tells me I'd need to sink 0.015v (again, whole values please ) through that resistor to get 10a....I'll probably get corrected on this though, but 0.015v/0.0015 Ohms=10a ?
The part I'm most interested in is the control feedback: how on earth will I be able to call up just 0.015v ? He uses a fancy voltage reference which can go down to the nearest millivolt, but I don't have one and here's where I get stuck...I'd need to have the control voltage on the non-inverting input at a more manageable level (say 5v or thereabouts), so the feedback to the inverting input would need to be amplified. What would a good op-amp be for such project as a whole and also how could I go about controlling the FET at such low values ? An amplifier stage would need to go in the feedback loop between the sense resistor and the non-inverting pin of the "main" op-amp...the gain would need to be huge, so I'm not sure it's really possible. LOTS of issues here. Let's talk about FET selection a little later on...for now, THIS is my main challenge.
The vid that inspired me is here. What the chap achieved is VERY tempting to replicate (100A load), but ultimately way overkill for my purposes, especially since I haven't actually designed one of these before and need to start small, so I'd say.....10A ? That's probably too much still (1A would probably do it for a beginner, but hey....think big ) The device is rather simple, or so it seems at first, because when I really began looking into it, I was quickly faced with one or two quirks I'd like to discuss.
I DID do my research do a degree, so let's go over this. The basic schematic is below. The main ingredients are a series-pass FET and sense resistor. I like to think of the FET as essentially shorting the PSU under test to ground through the resistor. For this reason, the resistor has to have a very small value so it doesn't burn up. The shunts the chap used in his project are 0.0015 ohm 50A shunts (yes, I much prefer using the whole value than using "MILLI..." etc....bare with us ). How do I know the value? For once, I happen to have the same exact shunts on hand (came with some of those panel ammeters you see on ebay...anyway) and also the current and voltage are stamped on the side, so here's where good ol' Ohm's law comes in to work out the voltage: V/R=I so 0.075V/0.0015 Ohms=50A...plain and simple (triple checked my math to make sure I don't make a fool out of myself for not knowing Ohm's law...which will probably happen anyway )
So now that we have the shunts, what do we do with them ? Our chap uses two in parallel to drop the resistance even more, but since I don't need to go too crazy with the current for now, 0.0015 ohms should be enough to achieve a 10a load. I have 3 of those shunts available, so my idea is to build 3 individual loads so I can stress multi-rail supplies simultaneously. My math tells me I'd need to sink 0.015v (again, whole values please ) through that resistor to get 10a....I'll probably get corrected on this though, but 0.015v/0.0015 Ohms=10a ?
The part I'm most interested in is the control feedback: how on earth will I be able to call up just 0.015v ? He uses a fancy voltage reference which can go down to the nearest millivolt, but I don't have one and here's where I get stuck...I'd need to have the control voltage on the non-inverting input at a more manageable level (say 5v or thereabouts), so the feedback to the inverting input would need to be amplified. What would a good op-amp be for such project as a whole and also how could I go about controlling the FET at such low values ? An amplifier stage would need to go in the feedback loop between the sense resistor and the non-inverting pin of the "main" op-amp...the gain would need to be huge, so I'm not sure it's really possible. LOTS of issues here. Let's talk about FET selection a little later on...for now, THIS is my main challenge.
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